Answer :
Answer:
45 000 N
Explanation:
[tex]pressure \: = \frac{force}{area} \\ density \times g \times height = \frac{force}{area} \\ (850)(9.81)(1.5) = \frac{force}{(2.4)(1.5)} \\ force \: = 45000n \: (3sf)[/tex]
The pressure the oil exerts on the base of the tank is required.
The oil exerts a force of 45027.9 N on the base of the tank.
The dimensions of the tank base are 2.4 m by 1.5 m.
h = The height of the tank = 1.5 m
[tex]\rho[/tex] = Density of oil = [tex]850\ \text{kg/m}^3[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
F = Force
A = Area of base
Pressure is given by
[tex]P=\rho gh[/tex]
[tex]P=\dfrac{F}{A}[/tex]
So,
[tex]\rho gh=\dfrac{F}{A}\\\Rightarrow F=\rho ghA\\\Rightarrow F=850\times 9.81\times 1.5\times (2.4\times 1.5)\\\Rightarrow F=45027.9\ \text{N}[/tex]
Hence, the oil exerts a force of 45027.9 N on the base of the tank.
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