Answer: 12
Step-by-step explanation:
Given the question :
Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?
The number of different positive two integer number can be obtained by:
P(4, 2) = 4P2
Recall:
nPr = n! / (n - r)!
4P2 = 4! / (4 - 2)!
4P2 = 4! / 2!
4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)
4P2 = 24 / 2
4P2 = 12
Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer
