Answered

The net fedrce on a 12 kg cart is 3.2N backward. Ignoring friction, what is the acceleration
of the car?
0.27 m/s2
3.8 m/s2
8.2 m/s2
18 m/s2
38m/s2

Answer :

Itzisabella

We have,

Mass,m = 12 kg

Force,F = 3.2 N

To be calculated:-

Calculate the acceleration ( a ) .

Solution:-

We know that,

[tex] \bf \: Force = Mass × Acceleration [/tex]

[tex] \sf\implies \: 3.2 = 12 \: \times a[/tex]

[tex] \sf \implies \: a = \dfrac{3.2}{12} [/tex]

[tex] \sf \implies \: a = \dfrac{32}{12 \times 10} [/tex]

[tex] \sf \implies \: a \: = \dfrac{8}{3 0} [/tex]

[tex] \sf \implies \: a = 0.266[/tex]

[tex] \sf \implies \: a = 0.27 \: m {s}^{ - 2} \: (approx)[/tex]

FadedElla

We are given with the amount of force applied and mass of a cart and we have to find the acceleration of the box.

  • Force applied = 3.2 N
  • Mass of the cart = 12 kg

According to Netwon's 2nd law,

After deriving, we will get that

  • Force = Mass × Accleration

Plugging the given values to get mass,

➝ 3.2 N = 12 kg × accleration

➝ Accleration = 3.2 / 12 m/s²

➝ Accleration = 0.27 m/s² (approx.)

Thus, the required answer is Option A.

Carry On Learning [tex]![/tex]

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