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use the equation below to determine what volume of nitrous oxide (n20) can be produced from the decomposition of 0.55 moles of ammonium nitrate (nh4no3).

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NH₄NO₃               →                   N₂O             + 2H₂O
1mol                       :                   22,4dm³
0,55mol                  :                   Vₓ

[tex]V_{x}=\frac{0,55mol*22,4dm^{3}}{1mol}=12,32dm^{3}[/tex]

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