Answer :

If the polynomial has zeros at 7 and 6 the equation will be
(X-7)(x-6)
When we distribute that we get
x^2-13x+42

A degree is the highest exponent of a polynomial. In this case the x^2. So the answer is 2

The minimum degree of the polynomial is 2.

Given the polynomial has zeros of 7, 6 means it has total of 2 zeroes. So it has only two factors possible [tex](x-7) and (x-6)[/tex] and on multiplying these factors we finally had a polynomial of degree 2 like[tex](ax^{2} +bx+c)[/tex].

So the given polynomial be a quadratic polynomial which has degree of 2.

Hence the minimum degree of the polynomial is 2.

For more details on quadratic polynomial follow the link:

https://brainly.com/question/18756459

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