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The perimeter of a rectangle is 88 ft. Its length is 16 ft more than the width. Find the dimensions of the rectangle

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NEED HELP ASAP | 25+ POINTS | IM BEGGING PLZ HELP | I NEED HELP NOW!! The perimeter of a rectangle is 88 ft. Its length is 16 ft more than the width. Find the d class=

Answer :

mhanifa

Answer:

  • 14 ft and 30 ft

Step-by-step explanation:

Perimeter is

P = 2(l+w), where l= length, w = width

  • P = 88
  • l = w + 16

Substitute values to find the value of w:

  • 88 = 2(w + 16 + w)
  • 2w + 16 = 44
  • 2w = 28
  • w = 14

Then

  • l = 14 + 16 = 30

Dimensions are 14 ft and 30 ft

captainkangas

Answer:

Perimeter is the sum of all sides added together.

Variables:

P=88

L=W+16

W=?

Equation:

88=2*(W+16+W)

Write with units:

L=30 ft.

W= 14ft.

Step-by-step explanation:

88=2*(W+16+W)

divide both sides by 2

44=W+16+W (This is one width and one length)

combine like terms

44=2W+16

subtract 16 from both sides

28=2W

divide both sides by 2

14=W

Your width is 14

Your length is 16 more than your width.

14+16=L

30=L

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