Answered

If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration
is -0.29 m/s??

Answer :

ladiposamson

Explanation:

u=24

v=0

a=-0.29

s=

v^2=u^2+2as

s=(v^2-u^2)/2a

s=(0-576)/0.58

s=-575.42

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