Answer:
Table (4)
Step-by-step explanation:
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
From the table (1),
Two points lying on the graph are (2, 1) and (6, -1).
Slope of the line = [tex]\frac{1+1}{2-6}[/tex] = [tex]-\frac{1}{2}[/tex]
From the table (2),
Two points lying on the linear function are (0, 8) and (2, 4).
Slope of the line = [tex]\frac{8-4}{0-2}[/tex] = -2
From the table (3),
Two points are (-4, 4) and (-2, 5).
Slope of the line = [tex]\frac{5-4}{-2+4}[/tex] = [tex]\frac{1}{2}[/tex]
From table (4),
Two points lying on the function are (-2, 0) and (0, 4).
Slope of the line = [tex]\frac{4-0}{0+2}=2[/tex]
Therefore, Table (4) represents a linear function with slope 2.
