Answer :

Answer:

3.07g of NaCl are present in the solution

Explanation:

A 1.05 M NaCl solution means you have 1.05 moles of NaCl per liter of solution. In 50.0mL = 0.0500L you will have:

0.0500L * (1.05mol / L) = 0.0525 moles of NaCl.

To convert these moles to grams you must use molar mass of the compound (Molar mass NaCl: 58.44g/mol). In 0.0525 moles of NaCl you will have:

0.0525mol * (58.44g / mol) =

3.07g of NaCl are present in the solution