Answer :
Answer:
[tex]y_{oe}=0.5x+0.15\\y_{ce}=1.25x^2+0.1\\\\[/tex]
for minimum cost the intersection point should be calculated i-e
[tex]0.5x+0.15=1.25x^2+0.1\\\\1.25x^2-0.5x-0.5=0\\[/tex]
By using calculator
[tex]x_1=0.4828\\x_2=-0.4828[/tex]
As x can't be negative so x=0.4828
It's the minimum value because as we decrease the operating cost further the capital value will increase so this is the minimum value.
Graphical solution:
