Answer :
Answer:
sp2
Explanation:
Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.
C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is sp2 hybridized.
Hence, the correct answer is "sp2".
The hybridization of the C atoms in C2Cl4 is sp² hybridized.
The concept of hybridization deals with the merging of atomic orbitals to produce fresh hybridized orbitals, which impact molecule geometry and bonding characteristics.
In the given compound, C2Cl4 (tetrachloroethene)
There is a substitution of all the hydrogen atoms attached to the organic compound ethene with chlorine to produce tetrachloroethene. The two carbon atoms are doubly bonded to each other with two chlorine attached to each of the carbon atoms diagonally given rise to a bond angle of 120°. Thus, the resulting hybridization of the C atom is sp² hybridized.
Therefore, we can conclude that the hybridization of the C atoms in C2Cl4 is sp² hybridized.
Learn more about hybridization here:
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