Equation of a line = y = mx +b
m = slope = change in y over the change in x
b = y intercept:
m = (-2 - 7) / (4 - -2) = -9/6 = -3/2
Now you have y = -3/2x + b
Use one of the points, replace y and x and solve for b:
7 = -3/2(-2) + b
Simplify:
7 = 3 + b
Subtract 3 from both sides:
b= 4
The equation is y = -3/2x + 4
Step-by-step explanation:
Hey there!.
The equation of a st.line passing through points (-2,7) and (4,2) is;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]
Put all values.
[tex](y - 7) = \frac{2 - 7}{4 + 2} (x + 2)[/tex]
Simplify it to get answer.
[tex](y - 7) = \frac{ - 5}{6} (x + 2)[/tex]
[tex]6(y - 7) = - 5(x + 2)[/tex]
[tex]6y - 42 = - 5x - 10[/tex]
[tex]5x + 6y - 42 + 10 = 0[/tex]
[tex]5x + 6y - 32 = 0[/tex]
Therefore the required equation is 5x+6y-32=0.
Hope it helps...
