Answer:
Lesser x is -13.
Greater x is 1.
Step-by-step explanation:
We have the function:
[tex]f(x)=(x+6)^2-49[/tex]
And we want to find the zeros of the function.
So, set f(x) to 0 and solve for x:
[tex](x+6)^2-49=0[/tex]
Add 49 to both sides:
[tex](x+6)^2=49[/tex]
Take the square root of both sides. Since we're taking an even root, we will need plus/minus:
[tex]x+6=\pm 7[/tex]
Subtract 6 from both sides:
[tex]x=\pm7-6[/tex]
Evaluate for each case:
Case 1; 7 is positive:
[tex]x=7-6=1[/tex]
Case 2; 7 is negative:
[tex]x=-7-6=-13[/tex]
So, our zeros are:
[tex]\{x|-13, 1\}[/tex]
Our lesser x is -13, and our greater x is 1.
And we're done!
Answer:
Our lesser x is -13, and our greater x is 1.
Step-by-step explanation:
