Answer :

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[tex]\tt Step-by-step~explanation:[/tex]

In order to solve for both x and y, we need to use the substitution property, where we replace a variable with what we solved for.

[tex]\tt Step~1:[/tex]

Let's solve for y first. Equation (1st one): 8x + 4y = 12. To isolate y, we can first subtract 8x from both sides, and then divide all terms by 4.

[tex]\tt 8x- (8x)+4y=12-(8x)\\4y=12-8x\\4y/4=y\\12/4=3\\-8x/4=-2x\\y=3-2x[/tex]

[tex]\tt Step~2:[/tex]

Then, we can solve for x. Let's take the second equation: 3x + y = 3. We take what we solved for in the previous step and plug it into this equation.

[tex]\tt 2x+(3-2x)=3\\2x+3-2x=3\\2x-2x=0\\3-3=0\\0=0\\x=x[/tex]

[tex]\large\boxed{\tt Our ~final~answer:(x,3-2x)}[/tex]

Both equations are also the same, so the solution = all real numbers for x.

[tex]\tt y=3-2x\\3-2x=3-2x[/tex]

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