Answer :
Answer:
v0 + 1/2at
Step-by-step explanation: Given that the distance a race car travels is given by the equation d = v0t+12at2 where v0 is the initial speed of the race car, a is the acceleration, and t is the time travelled.
The equation for the driver's average speed s during the acceleration will be:
(v0t+12at2) / t
Since Average speed is equal to distance divided by time.
Therefore, the equation will be:
v0+1/2at
The average speed s (technically average velocity) at time t will be given by the equation:
[tex]s = v_0 + \dfrac{1}{2} \times a \times t[/tex]
Given that:
If d denotes the distance travelled by the car with initial velocity [tex]v_0[/tex] and acceleration a, then:
[tex]d = v_0\times t + \dfrac{1}{2} \times a \times t^2[/tex]
And since average speed is total distance divided by total time taken, thus let the average speed is denoted by s, then:
[tex]s = v_0 + \dfrac{1}{2} \times a \times t[/tex]
The terms speed and distance here, are technically referring to the terms velocity and displacement respectively since speed and distance are scalar quantities.
For more information, refer to this link below:
https://brainly.com/question/862972