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The lab technician you recently hired tells you the following: Boss, an undisturbed sample of saturated clayey soil was brought to me from the Mission Valley site. I measured the mass of the sample to be 600 grams. I then measured the mass of the sample after placing it in the oven for 24 hrs. I found this mass to be 200 grams. Can you help me determine the water content?" Determine the water content.

Answer :

onyebuchinnaji

Answer:

The water of the saturated clayed soil is 66.67 %.

Explanation:

Given;

mass of saturated clayed soil, [tex]M_s[/tex] = 600 g

mass of dry soil sample, [tex]M_d[/tex] = 200 g

mass of water content, [tex]M_w[/tex] = [tex]M_s[/tex] - [tex]M_d[/tex] = 600 g - 200 g = 400 g

The water content is determined as;

[tex]M_w(\%) = \frac{M_s - M_d}{M_s} *100\%\\\\M_w(\%) = \frac{600-200}{600} *100 \% \\\\M_w(\%) = 66.67 \%[/tex]

Therefore, the water of the saturated clayed soil is 66.67 %.

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