Answer:
[tex]x_1 = 1[/tex]
[tex]x_2=0[/tex]
Step-by-step explanation:
The question is incomplete as the method is not given.
However, the question can still be solved.
Given
[tex]x_1 - x_2 = 1[/tex]
[tex]3x_1 + x_2 = 3[/tex]
Make xi the subject in the first equation
[tex]x_1 = 1 + x_2[/tex]
Substitute 1 + x2 for xi in the second equation
[tex]3(1+x_2)+x_2 = 3[/tex]
Open bracket
[tex]3+3x_2+x_2=3[/tex]
[tex]3+4x_2=3[/tex]
Collect Like Terms
[tex]4x_2 = 3-3[/tex]
[tex]4x_2 =0[/tex]
Solve for x2
[tex]x_2=0/4[/tex]
[tex]x_2=0[/tex]
Recall that:
[tex]x_1 = 1 + x_2[/tex]
[tex]x_1 = 1+0[/tex]
[tex]x_1 = 1[/tex]
