Find the value of b for the triangle using the Pythagorean Theorem.

Step-by-step explanation:
Hey there!
Given;
The given figure is a Right angled triangle, taking reference angle as angle B.
Hypotenuse= AB=5
Base= CB= 4
Perpendicular= AC=b
Using Pythagorean theorem.
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
[tex]p = \sqrt{ {h}^{2} - {b}^{2} } [/tex]
Put all values.
[tex]b = \sqrt{ {5}^{2} - {4}^{2} } [/tex]
[tex]b = \sqrt{25 - 16} [/tex]
[tex]b = \sqrt{9} [/tex]
Therefore, the value of b is 3.
Hope it helps...