atecno2563
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the motion of car is drawn is v against t graph as in figur
A. what is the acceleration of the car???
B. what is distance travled by the car in 60 seconds​????

the motion of car is drawn is v against t graph as in figurA. what is the acceleration of the car???B. what is distance travled by the car in 60 seconds​???? class=

Answer :

saloni28

Answer:

a) Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

b) Using the equation  equals plus a half squared gives us is equal to 13.5 multiplied by 10 plus a half multiplied by an eighth multiplied by 10 squared. This gives us a value of of 141.25. Therefore, the total distance covered by the body in the first 10 seconds of its motion is 141.25 meter.

Explanation:

hy this isn't the proper answer but by checking these equations you can get your answer .

hnori22003

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A )

[tex]acceleration = \frac{∆v}{∆t} = slope \\ [/tex]

Thus ;

[tex]acceleration = 2 \: \: \frac{m}{ {s}^{2} } [/tex]

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B )

[tex]v(t) = 2t[/tex]

So ;

[tex]v(60) = 2 \times (60)[/tex]

[tex]v(60) = 120[/tex]

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Point :

The area which is under the figures in v-t graphs , shows the distance traveled.

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Thus ;

[tex]distance \: traveled = \frac{1}{2} \times (60) \times 120 \\ [/tex]

[tex]distance \: traveled \: = 30 \times 120 \\ [/tex]

[tex]distance \: traveled \: = 3600 \: \: meters \\ [/tex]

Done...

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