Answered

A spring has a spring stiffness constant k of 85.0 N/m . How much must this spring be compressed to store 25.0 J of potential energy

Answer :

samuelonum1

Answer:

0.76m

Explanation:

We know that the expression for the energy stored in a spring is given as

E= 1/2kx²

Given data

K=85N/m

E=25j

Substituting we have

25= 1/2(85)*x²

2*25=85x²

x²=50/85

x²=0.588

x=√0.588

x=0.76m

the spring must be compressed to 0.76m

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