Answer :
Answer:
231.59 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 125 mL
Initial temperature (T₁) = 300 k
Initial pressure (P₁) = 2.39 atm
Final temperature (T₂) = 500 k
Final pressure (P₂) = 2.15 atm
Final volume (V₂) =..?
The new volume of the gas (V₂) can be obtained by using the combined gas equation as shown below:
P₁V₁ /T₁ = P₂V₂ /T₂
2.39 × 125 /300 = 2.15 × V₂ /500
Cross multiply
300 × 2.15 × V₂ = 2.39 × 125 × 500
645 × V₂ = 149375
Divide both side by 645
V₂ = 149375/645
V₂ = 231.59 mL
Therefore, the new volume of the gas is 231.59 mL