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There are two possible angles, relative to the horizontal, that the ball could have been kicked. What is the smallest of those two angles

Answer :

Answer:

The smallest of those two angles is 20°

Explanation:

Here , v = 30m/s

        range = 59m

     Range =[tex]\frac{u^2sin2\theta}{g}[/tex]

           59     =[tex]\frac{30\times30\times sin2\theta}{9.8}[/tex]

              [tex]sin2\theta=\frac{59\times9.8}{30\times30}[/tex]

               [tex]2\theta=40[/tex]°

                [tex]\theta=[/tex] 20°    (since 90° -20°= 70°)

Therefore , the two angles are 20° and 70°

Among the both , the smallest angle is 20°

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