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4.) A boat heading north crosses a wide river at a velocity of 2.778 m/s. The river current pushes the boat east at a constant velocity of 1.389 m/s. Find the resultant velocity. a.) 3.11 m/s b.) 9.65 m/s c.) 0.78 m/s d.) 6.38 m/s​

Answer :

Answer:

Resultant velocity = 3.11 m/s.

Explanation:

It is given that,

The velocity of a boat is 2.778 m/s due North

The velocuity of river is 1.389 m/s due east.

We need to find the resultant velocity. The angle between these two velocities is 90 degrees. The resultant is given by :

[tex]v=\sqrt{v_b^2+v_r^2} \\\\v=\sqrt{2.778 ^2+1.389 ^2} \\\\v=3.11\ m/s[/tex]

So, the correct option is (a).

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