Answer :
Answer:
[tex]\frac{1}{2}[/tex] Option A.
Step-by-step explanation:
A locker combination has three nonzero, non-repeated digits.
Total possibilities for the first place would be = 9 digits
Total possibilities for the second place would be = 8 digits [out of 9 no. 1 number is chosen]
and for the third place the possibilities of digits = 7 digits.
If the first digit is odd.
For the second place the even numbers are = 2, 4, 6, and 8
So the probability that the second digit is even = [tex]\frac{4}{8}[/tex] = [tex]\frac{1}{2}[/tex]
Option A. [tex]\frac{1}{2}[/tex] is the answer.
Answer:
the answer is actualy b
Step-by-step explanation:
i tried the other answer from the other guy and it was incorrect
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