Answer:
The horizontal distance traveled by the rocket is 90.46 m
Explanation:
Given;
initial velocity of the rocket, u = 30 m/s
angle of projection, θ = 40°
the horizontal distance traveled by the rocket = ?
The horizontal distance traveled by the rocket is given by the range of the projectile.
The range of the projectile is given as;
[tex]R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m[/tex]
Therefore, the horizontal distance traveled by the rocket is 90.46 m
The closest answer in the given options is 90.54 m
