Answer :
Answer:
The three integers are 12,13 and 14
Step-by-step explanation:
Let
x,x+1,x+2 be three consecutive integers.
Out of these, the smallest one is x and largest is x+2 as it comes at last in the integers.
So according to given statement
[tex]x+(x+1)+(x+2) = 4x-9[/tex]
This is a linear equation in one variable, which can simply be solved by using equality properties
[tex]x+x+1+x+2 = 4x-9\\3x+3 = 4x-9[/tex]
Subtracting 4x from both sides
[tex]3x+3-4x = 4x-9-4x\\-x+3=-9[/tex]
Subtracting 3 from both sides
[tex]-x+3-3 = -9-3\\-x = -12\\x = 12[/tex]
The smallest integer is 12.
The other integers are:
x+1 = 12+1 = 13
x+2 = 12+2 = 14
Hence,
The three integers are 12,13 and 14