Answer :
Answer:
b.) intersection
Step-by-step explanation:
The given inequality can be rearranged so that you can see the solution space is one continuous interval.
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It is described by the intersection of two inequalities.
|y -3| -4 ≤ -3 . . . . . . given
|y -3| ≤ 1 . . . . . . . . add 4
-1 ≤ y -3 ≤ 1 . . . . . "unfolded", the intersection of two inequalities
2 ≤ y ≤ 4 . . . . . . . add 3
This means 2 ≤ y and y ≤ 4, the intersection of the two inequalities.
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Additional comment
If the inequality were of the form ...
|y -3| ≥ 1
then it would "unfold" to ...
-1 ≥ y -3 or y -3 ≥ 1
and the solution intervals would be disjoint. The solution would be the union of the solution intervals of the individual inequalities.