Answer:
The object takes approximately 1.180 seconds to complete one horizontal circle.
Explanation:
From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ([tex]a[/tex]), measured in meters per square second, is entirely centripetal and is expressed as:
[tex]a = \frac{4\pi^{2}\cdot R}{T^{2}}[/tex] (1)
Where:
[tex]T[/tex] - Period of rotation, measured in seconds.
[tex]R[/tex] - Radius of rotation, measured in meters.
If we know that [tex]a = 26.36\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.93\,m[/tex], then the time taken by the object to complete one revolution is:
[tex]T^{2} = \frac{4\pi^{2}\cdot R}{a}[/tex]
[tex]T = 2\pi\cdot \sqrt{\frac{R}{a} }[/tex]
[tex]T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }[/tex]
[tex]T \approx 1.180\,s[/tex]
The object takes approximately 1.180 seconds to complete one horizontal circle.
