Answer :
☄Given:
- [tex]\sf{Average\:speed = 21km/h}[/tex]
- [tex]\sf{Time\:taken=40\:minutes}[/tex]
☄To find:
- [tex]\sf{distance=?}[/tex]
★Formula used:
[tex]\boxed{Average\:speed=\frac{Total\:distance}{Total\:time\:taken}}[/tex]
★Solution:
[tex]\bold{\underline{\underline{As\:we\:know\:all\:the\:units\:are\:in\:hr}}}[/tex]
[tex]\rm{So,40\:minutes=\frac{40}{60}=\frac{2}{3}}[/tex]
[tex]\sf{\underline{\underline{Now,putting\:values\:in\:the\:given\:formula:}}}[/tex]
[tex]\rm{21km/h=\frac{Distance}{\frac{2}{3}}}[/tex]
[tex]\rm→{21×\frac{2}{3}=Distance}[/tex]
[tex]\rm{→14=Distance}[/tex]
______________________________
[tex] \large{ \underline{ \overline{ \mid{ \rm{ \red{Answer→Distance=14\:\:km}} \mid}}}}[/tex]
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Answer:
[tex]we \: have \: avarage \: speed= \frac{distance}{time \: } \\ here \: time \: is \: in \: \: minute \: convert \: \\ it \: in \: to \: hour \\ so \: \frac{40}{60} \: hour \\ = \frac{2}{3} hour \\ distance = avarage \: speed \times time \\ = 21 \times \frac{2}{3} = 7 ×2 = 14km\\ thank \: you[/tex]