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What is the equation of the line, in general form, that passes through the point (1, 1) and has a y-Intercept
of 2
Ox+y20
Ox-y + 20
OX-y-20

Answer :

quasarJose

Answer:

y = -x + 2

Step-by-step explanation:

The equation of line is often written in the form;

     y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

 From the given parameters;

        c  = 2

     (1,1) are the coordinates

Let us find the slope of the line;

      1  = m(1) + 2

       1  = m + 2

          m = 1- 2  = -1

The equation of the line is;

         y  = -1x + 2

         y = -x + 2

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