Answer :
Answer:
The kinetic coefficient of friction of the sled on the snow is 0.05
Explanation:
The given parameters are;
The weight of the sled Jill is pulling, W = 200 N
The force with which Jill is pulling the the sled = 10 Newtons
The nature of the speed with which the sled is pulled = Constant speed
Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;
The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction, [tex]F_k[/tex]
The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow, [tex]\mu _k[/tex]
[tex]F_k[/tex] = W × [tex]\mu _k[/tex]
[tex]\mu _k[/tex] = [tex]F_k[/tex]/W = 10 N/(200 N) = 0.05
The kinetic coefficient of friction of the sled on the snow = [tex]\mu _k[/tex] = 0.05.