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Four milliliters of ink A is added to 10 milliliters of ink B, forming a mixture of inks. Ink A contains 10% blue pigment. Ink B contains an unknown percentage of blue pigment. The mixture of the two inks contains 35% blue pigment. Solve for the percentage of blue pigment is in the mixture of the two inks. A. 45% B. 49% C. 60% D. 75%

Answer :

Thank you for posting your question here at brainly. The answer to the above problem is letter A which is 45%. Below is the solution:

The amount of Blue pigment is fixed so 4*(10/100)+10*(x/100) = 14*(35/100) x = 45

Hope it helps. 
scme1702
The question involves what is referred to as a mass balance and can be solved as follows:
Ink A is:
total = 4ml
blue = 4 x 0.1 = 0.4ml
remaining = 3.6ml
Ink B is:
total = 10ml
blue = x
Remaining = 10 - x
Now, upon combination:
total = 4ml + 10ml = 14ml
Blue = 14ml * 0.35 = 4.9ml
Blue in total = blue in A + blue in B
4.9 = 0.4 + x
x = 4.5ml
Percentage of blue ink in B = 4.5/10 x 100
= 45%
The answer is A

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