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A person is sledding down a hill at a speed of 9 m/s. The hill gets steeper and his speed increases to 18 m/s in 3 sec. What was his acceleration?​

Answer :

kyliejohns10

Answer:

3 m/s^2

Explanation:

You are given their initial velocity and their final velocity, as well as the time.

This allows you to use the equation for acceleration, a = Δv/Δt (change in velocity over change in time):

vfinal - vinitial = Δv

(18 m/s - 9 m/s)/ 3 sec = 3 m/s^2

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