Find the tenth term of the geometric sequence with a1 = 3, and r = 2.
1377
1526
1659
1536
1500

General term of GP: a
1
r
n−1
10
th
term of GP =a
1
r
9
=45(0.2)
9
=23040×10
−9
=2.304×10
−5
Answer:
1536
Step-by-step explanation:
The n th term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex]r^{n-1}[/tex]
Here a₁ = 3 and r = 2 , then
a₁₀ = 3 × [tex]2^{9}[/tex] = 3 × 512 = 1536