When Joseph first starts working at a grocery store, his hourly rate is $ 10 $10dollar sign, 10. For each year he works at the grocery store, his hourly rate increases by $ 0.50 $0

Answer :

MrRoyal

Answer:

[tex]y = 10+ 0.50 x[/tex]

Step-by-step explanation:

Given

[tex]Initial = \$10[/tex]

[tex]Increment = \$0.50[/tex] -- yearly

Required

Represent as a function (this is the missing part of the question)

The given details show that the question illustrates linear function

i.e.

[tex]y = b + mx[/tex]

In this case, it is:

[tex]Current\ Rate = Initial + Increment * Years[/tex]

Represent the current rate with y and the years with x.

So, we have:

[tex]y = Initial + Increment * x[/tex]

Substitute 10 for Initial and 0.5 for Increment

[tex]y = 10+ 0.50 * x[/tex]

[tex]y = 10+ 0.50 x[/tex]

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