kodymilford2
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The circle below is centered at the point (5,3) and has a radius of length 4.
What is its equation?
O A. (x+3)2 + (y + 5)2 =
16
B. (x + 5)2 + (y + 3)2 =
16
10
O C. (x - 5)2 + (y - 3)2 =
16
O D. (x-3)2 + (y - 5)2 = 16

The circle below is centered at the point (5,3) and has a radius of length 4. What is its equation? O A. (x+3)2 + (y + 5)2 = 16 B. (x + 5)2 + (y + 3)2 = 16 10 O class=

Answer :

The circle equation is (x-5)’2+(y-3)’2=16

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