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The height (in centimeters) at time t (in seconds) of a small mass oscillating at the end of a spring is h(t)=5sin(2πt). Estimate its instantaneous velocity at t=3

Answer :

Answer:

 h (3) = 0

Explanation:

In this exercise they give us the expression that governs the movement

           h (t) = 5 sin (2πt)

remember that the angles are in radians.

To calculate the instantaneous velocity we substitute

           h (3) = 5 sin (2π 3)

           h (3) = 0

therefore the body this is its position of equilibrium

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