Answer :
Answer:
Step-by-step explanation:
(x,y) ↦ (x+130, y-105)
original position of SE corner: (-50,25)
new position of SE corner: (80,-80)
distance = [tex]\sqrt{(80-(-50))^{2}+(-80-25)^{2} }[/tex]≅167.1 ft
Answer:
Step-by-step explanation:
(x,y) ↦ (x+130, y-105)
original position of SE corner: (-50,25)
new position of SE corner: (80,-80)
distance = [tex]\sqrt{(80-(-50))^{2}+(-80-25)^{2} }[/tex]≅167.1 ft