Answer :
Answer:
[tex]\text{For topic A }:0.99\\\text{For Topic B}: 0.6875[/tex]
Step-by-step explanation:
Topic A: Two books are ordered
Topic B: Four books are ordered
Let X= number of books arrived
The probability that a book actually arrives in time is 0.9
i.e., p=0.9
For Topic A:
[tex]P(X\geq 1)=P(X=1)+P(X=2)\\\Rightarrow P(X\geq 1)= \;^2C_1 (0.9)^1(0.1)^(2-1)+\;^2C_2 (0.9)^2(0.1)^(2-2)\\\Rightarrow P(X\geq 1)=0.18+0.81\\\Rightarrow P(X\geq 1)=0.99[/tex]
For Topic B:
[tex]P(X\geq 2)=P(X=2)+P(X=3)+P(X=4)\\\Rightarrow P(X\geq 2)=1-[P(X=0)+P(X=1)]\\\Rightarrow P(X\geq 2)=1-[\;^4C_0(0.5)^0(0.5)^4 +\;^4C_0(0.5)^1(0.5)^3]\\\Rightarrow P(X\geq 2)=1-[0.0625+0.25]\\\Rightarrow P(X\geq 2)=0.6875[/tex]