1.

Archaeologists have discovered the legendary Golden Igloo of the Pribiloff Islands, a structure consisting of a

halfspherical shell with an inner diameter of 1.25 m and an out diameter of 1.45 m. What is the value of this antiquity,

given that gold currently sells for $1,263/ounce and has a density of 19.3 g/cm3? (Note that 1 ounce = 31.1034768 g)

Answer :

whitneytr12

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

[tex] V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3} [/tex]

[tex] V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3} [/tex]

The total volume is given by:

[tex] V_{T} = V_{o} - V_{i} [/tex]

Where:

[tex] V_{i} [/tex]: is the inner volume

[tex]r_{i}[/tex]: is the inner radius = 1.25/2 = 0.625 m

[tex] V_{o} [/tex]: is the outer volume

[tex]r_{o}[/tex]: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

[tex] V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3} [/tex]

Now, by using the density we can find the mass of the Igloo:

[tex] m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g [/tex]

Finally, the value (V) of the antiquity is:

[tex] V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6} [/tex]  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

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