Answer :
Answer:
At t=2s the car reach its minimum speed
Minimum speed=8m/s
Step-by-step explanation:
We are given that velocity of car
[tex]v(t)=t^2-4t+12[/tex]
0<t<4
Differentiate w.r.t t
[tex]v'(t)=2t-4[/tex]
[tex]v'(t)=0[/tex]
[tex]2t-4=0[/tex]
[tex]2t=4[/tex]
[tex]t=2[/tex]
[tex]v''(t)=2>0[/tex]
The velocity is minimum at t=2 s
Substitute t=2
[tex]v(2)=2^2-4(2)+12[/tex]
[tex]v(2)=8m/s[/tex]
Hence, the speed of car is minimum at t=2 se and minimum speed of car=8m/s