Answer:
Step-by-step explanation:
For the single triangle
sin60=h/14, h=14sin60
cos60=b/(2(14)), b/2=14cos60 so the total area is nhb/2 where n is the number of sides
A=n(14sin60)(14cos60), since n=6
A=6(14sin60)(14cos60)
A=114.75cm^2
The hexagon is divided into 6 equal triangles. Then the area of the base of the pyramid is 509 square cm.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The base of a regular pyramid is a hexagon.
The hexagon is divided into 6 equal triangles. Then the height of the triangle will be
[tex]\rm a = 14 \sin 60^o\\\\a = 12.12[/tex]
Then the area of the triangle will be
[tex]\rm Area \ of \ triangle = 0.5 \times 14 \times 12.12\\\\Area \ of \ triangle = 84.84 \ cm^2[/tex]
Then the area of the base of the pyramid will be
[tex]\rm Area \ of \ base \ pyramid = 6 \times Area \ of \ triangle\\\\Area \ of \ base \ pyramid = 6 \times 84.84\\\\Area \ of \ base \ pyramid = 509.04 \approx 509 \ \ cm^2[/tex]
More about the geometry link is given below.
https://brainly.com/question/7558603
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