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If the molecules in the above illustration react to form NH3 according to the equation N2 3 H2 2 NH3 , the limiting reagent is , the number of NH3 molecules formed is , and the number of molecules in excess is

Answer :

Answer:

Follows are the solution to these question:

Explanation:

Given equation:

[tex]N_2+3H_2 \longrightarrow 2NH_3[/tex]

In this equation:

[tex]1 N_2[/tex] gives [tex]= 2NH_3[/tex]

so,

[tex]3N_2[/tex] gives=  [tex]2 \times 3 = 6 NH_3[/tex]

similarly:

[tex]3H_2[/tex] gives [tex]= 2NH_3[/tex]

So, [tex]6H_2[/tex] gives = [tex]\frac{2}{3}\times 6=4NH_3[/tex]

Its limited reagent is =[tex]N_2[/tex]

The amount of [tex]NH_3[/tex] molecules were formed = 4.

and the amount of  [tex]H_2[/tex] excess molecules are= 1

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