Answer :
sin( pi /4 * t - pi/2 ) = sqrt(3)/2
we know that when theta = Pi/3, sin (Pi/3) = sqrt(3)/2
so solve Pi/3 = Pi/4 * t - Pi/2
Pi/2 + Pi/3 = Pi/4 * t
I am not really sure. Sorry :(
we know that when theta = Pi/3, sin (Pi/3) = sqrt(3)/2
so solve Pi/3 = Pi/4 * t - Pi/2
Pi/2 + Pi/3 = Pi/4 * t
I am not really sure. Sorry :(