Helpful steps please, A coil of wire rotating in a magnetic field induces a voltage given by e = 20 sin ((piT/4)-(pi/2)). where t is time in seconds. Find the smallest positive time to produce a voltage of 10 square root 3.

Answer :

Candyluv16
sin( pi /4 * t - pi/2 ) = sqrt(3)/2
we know that when theta = Pi/3, sin (Pi/3) = sqrt(3)/2
 so solve Pi/3 = Pi/4 * t - Pi/2
 Pi/2 + Pi/3 = Pi/4 * t

I am not really sure. Sorry :(

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