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This equation shows the combustion of methanol.

2CH2OH(1) +302(g) → 2C02(g) + 4H2O(g)

How many liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol
(CH3OH)

A. 44.8L
B. 89.6 L
C. 11.2L. D. 22.4L

Answer :

Answer: 44.8 L

Explination:

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