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What is the equation, in point-slope form, for a line that goes through (8, −4)(8, −4) and has a slope of −56−56 ?
y−4=−56(x+8)
y+4=−56(x+8)
y+4=−56(x−8)
y−4=−56(x−8)

Answer :

nini2018s5

Hope this helped out! :)

Answer:

${teks-lihat-gambar} nini2018s5

The equation of the line, in point-slope form, is given by:

[tex]y + 4 = -\frac{5}{6}(x - 8)[/tex], given by the third option.

The equation of a line, in point-slope form, has the following format:

[tex]y - y_0 = m(x - x_0)[/tex]

In which:

  • The slope is m.
  • The point is [tex](x_0, y_0)[/tex].

In this problem:

  • Point (8, -4), thus [tex]x_0 = 8, y_0 = -4[/tex].
  • Slope of -5/6, thus [tex]m = -\frac{5}{6}[/tex]

The equation is:

[tex]y - y_0 = m(x - x_0)[/tex]

[tex]y - (-4) = -56(x - 8)[/tex]

[tex]y + 4 = -\frac{5}{6}(x - 8)[/tex]

A similar problem is given at https://brainly.com/question/13967935

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