Answered

the function f(x)=tan(3/2x-pi/2) has:

A) period pi/3 and asymptote at x=pi/3

B) period 2pi/3 and asymptote at x=0

C) period 2pi/3 and asymptote at x=pi/3

D) period pi/3 and asymptore at x=0

Answer :

pkmnmushy
I think the best option here is B. period 2pi/3 and asymptote at x=0
because period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3. I hope this can work good for you. 

Answer:

B

Step-by-step explanation:

A PEx

Other Questions