Answer :
For the first part: F'(20) can be approximated by finding the secant line on boundaries that hold x=20 while being as small as given. [15, 30] satisfies this. Thus F'(20) is approximated by F(30)−F(15)/30−15=−1−(−3)/15=2/15
Now for the second part: We prove b) using the mean value theorem for derivatives. SO:
x= 2 and x= -3 is -1/12. It is also given that f(x) is differentiable in [-3,2]. Wecan see from here that it is continuous at a point. Thus, we can assume that it is differentiable in [-3,2] and continuous on [-3, 2].
Now for the third part: Lastly, the intermediate value theorem allows us to prove c. Then there is a point c2 such that f(c2) = 0. We proved in the previous part that there exists a finite closed interval [a,b]. Also, there's f(30) = -1 and f(45) which satisfy the other requirement for this theorem
I hope this is what you need.
Now for the second part: We prove b) using the mean value theorem for derivatives. SO:
x= 2 and x= -3 is -1/12. It is also given that f(x) is differentiable in [-3,2]. Wecan see from here that it is continuous at a point. Thus, we can assume that it is differentiable in [-3,2] and continuous on [-3, 2].
Now for the third part: Lastly, the intermediate value theorem allows us to prove c. Then there is a point c2 such that f(c2) = 0. We proved in the previous part that there exists a finite closed interval [a,b]. Also, there's f(30) = -1 and f(45) which satisfy the other requirement for this theorem
I hope this is what you need.