Answer :
The solution to the problem is as follows:
4 sqrt(16x^2 y^7)
Protip: sqrt(abc) = sqrt(a)sqrt(b)sqrt(c). Therefore,
4sqrt(16x^2y^7) = 4sqrt(16)sqrt(x^2)sqrt(y^7)
We can deal with sqrt(16); it is equal to 4.
4(4) sqrt(x^2)sqrt(y^7)
16sqrt(x^2)sqrt(y^7)
Next, it is a known fact that sqrt(z^2) is the same as |z|, or the absolute value of z. That means
sqrt(x^2) = |x|
16|x| sqrt(y^7)
Split y^7 as y^6 * y
16|x| sqrt(y^6 * y)
16|x| sqrt(y^6) sqrt(y)
16|x| sqrt([y^3]^2) sqrt(y)
16|x| |y^3| sqrt(y)
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 sqrt(16x^2 y^7)
Protip: sqrt(abc) = sqrt(a)sqrt(b)sqrt(c). Therefore,
4sqrt(16x^2y^7) = 4sqrt(16)sqrt(x^2)sqrt(y^7)
We can deal with sqrt(16); it is equal to 4.
4(4) sqrt(x^2)sqrt(y^7)
16sqrt(x^2)sqrt(y^7)
Next, it is a known fact that sqrt(z^2) is the same as |z|, or the absolute value of z. That means
sqrt(x^2) = |x|
16|x| sqrt(y^7)
Split y^7 as y^6 * y
16|x| sqrt(y^6 * y)
16|x| sqrt(y^6) sqrt(y)
16|x| sqrt([y^3]^2) sqrt(y)
16|x| |y^3| sqrt(y)
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!