Answer :

abidemiokin

Answer:

aₙ = -2aₙ₊₁

Step-by-step explanation:

According to the sequence given 16, -8, 4, ...

a1 = 16

a2 = -8

a3 = 4

From the values, we can conclude thst;

a1 = -2(-8)

Since a2 = -8, then;

a1 = -2(a2)

Similarly

a2 = -2(4)

a2 = -2a3

The subsequent sequence are;

a3 = -2a4

The nth term will ne;

aₙ = -2aₙ₊₁

Hence the required recursive function is aₙ = -2aₙ₊₁

The recursive formula for the given sequence is

[tex]a_{n}=-\frac{1}{2} (a_{n-1})\\[/tex]

Given :

The terms of the sequence are  16, -8, 4, ...

Lets find the difference between the terms

[tex]-8-16=-24\\4-(-8)=12[/tex]

There is no common difference. So this is not an arithmetic sequence

Now we check common ratio'

[tex]\frac{-8}{16} =-\frac{1}{2} \\\frac{4}{-8} =-\frac{1}{2} \\[/tex]

The common ratio is -1/2

Now we write recursive formula

[tex]a_{n}=r(a_{n-1})[/tex]

Where 'r' is the common ratio

[tex]a_{n}=r(a_{n-1})\\a_{n}=-\frac{1}{2} (a_{n-1})\\[/tex]

The recursive formula is

[tex]a_{n}=-\frac{1}{2} (a_{n-1})\\[/tex]

Learn more :  brainly.com/question/24231459

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